Andy wrote:
> Hi, the file below will print all the keywords in a file and also the
> line # of the keyword. What I couldn't figure out is to count those
> keywords per line. For example - "Line #1 has 3 keywords"
>
> Can I do like -
>
> total[j] = total[j] + numwords(k)
> "Line number %d has %d keywords" % (j, total[j])
>
> Seems sort of "illegal" in Python?
>
>
>
> -------------------------------------------------
> import keyword, sys, string, fileinput
> def numwords(s):
> list = string.split(s)
> return len(list)
>
> # Get the file name either from the command-line or the user
> if len(sys.argv) != 2:
> name = raw_input("Enter the file name: ")
> else:
> name = sys.argv[1]
>
> inp = open(name,"r")
> linelist = inp.readlines()
> total, words,lines = 0, 0, 0
>
> for i in range(len(linelist)):
> line = linelist[i]
> tempwords = line.split()
> for k in tempwords:
> if keyword.iskeyword(k):
> total = total + numwords(k)
> j = i + 1
> print" The word * %s * belongs in line number: %d" % (k,
> j)
>
> print "Total keywords in this file are: %d" %(total)
>
You probably want something that goes a little like this:
for i,line in enumerate(linelist):
for k in line.split():
if keyword.iskeyword(k):
total += line.count(k)
print "The word '%s' belongs in line num: %d" % (k, i+1)
print "Total keyords are: %d" % total
James
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