On May 3, 9:44 am, Johny <[EMAIL PROTECTED]> wrote: > On May 3, 4:37 pm, [EMAIL PROTECTED] wrote: > > > > > On May 3, 9:27 am, Johny <[EMAIL PROTECTED]> wrote: > > > > Let's suppose > > > s='12345 4343 454' > > > How can I replace the last '4' character? > > > I tried > > > string.replace(s,s[len(s)-1],'r') > > > where 'r' should replace the last '4'. > > > But it doesn't work. > > > Can anyone explain why? > > > > Thanks > > > L. > > > I think the reason it's not working is because you're doing it kind of > > backwards. For one thing, the "string" module is deprecated. I would > > do it like this: > > > s = s.replace(s[len(s)-1], 'r') > > > Although that is kind of hard to read. But it works. > > > Mike > > Mike it does NOT work for me.>>> s.replace(s[len(s)-1], 'r') > > '123r5 r3r3 r5r' > > I need only the last characte
Yeah...I'm an idiot. Sorry about that. Listen to the other users! Mike -- http://mail.python.org/mailman/listinfo/python-list
