Greg Corradini wrote:
>
> Hello all,
> I'm having trouble understanding why the following code evaluates as it
> does:
>
>>>> string.find('0200000914A','.') and len('0200000914A') > 10
> True
>>>> len('0200000914A') > 10 and string.find('0200000914A','.')
> -1
>
> In the 2.4 Python Reference Manual, I get the following explanation for
> the 'and' operator in 5.10 Boolean operations:
> " The expression x and y first evaluates x; if x is false, its value is
> returned; otherwise, y is evaluated and the resulting value is returned."
>
> Based on what is said above, shouldn't my first expression (
> string.find('0200000914A','.') and len('0200000914A') > 10) evaluate to
> false b/c my 'x' is false? And shouldn't the second expression evaluate to
> True?
The first evaluates to True because len(...) > 10 will return a boolean -
which is True, and the semantics of the "and"-operator will return that
value.
And that precisely is the reason for the -1 in the second expression.
y=-1
and it's just returned by the and.
in python, and is implemented like this (strict evaluation nonwithstanding):
def and(x, y):
if bool(x) == True:
return y
return x
Diez
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