Cesar G. Miguel <[EMAIL PROTECTED]> wrote: > On May 12, 3:40 pm, Dmitry Dzhus <[EMAIL PROTECTED]> wrote: > > > Actually I'm trying to convert a string to a list of float numbers: > > > str = '53,20,4,2' to L = [53.0, 20.0, 4.0, 2.0] > > > > str="53,20,4,2" > > map(lambda s: float(s), str.split(',')) > > > > Last expression returns: [53.0, 20.0, 4.0, 2.0] > > -- > > Happy Hacking. > > > > Dmitry "Sphinx" Dzhushttp://sphinx.net.ru > > Nice!
As somebody else alredy pointed out, the lambda is supererogatory (to say the least). > The following also works using split and list comprehension (as > suggested in a brazilian python forum): > > ------------------- > L = [] > file = ['5,1378,1,9', '2,1,4,5'] > str='' > for item in file: > L.append([float(n) for n in item.split(',')]) The assignment to str is useless (in fact potentially damaging because you're hiding a built-in name). L = [float(n) for item in file for n in item.split(',')] is what I'd call Pythonic, personally (yes, the two for clauses need to be in this order, that of their nesting). Alex -- http://mail.python.org/mailman/listinfo/python-list