James Stroud wrote:
It seems I need constructs like this all of the time
i = 0 while i < len(somelist): if oughta_pop_it(somelist[i]): somelist.pop(i) else: i += 1
There has to be a better way...
Do you have to modify your list in place?
If not, just create a copy with the filtered items:
somelist = [item for item in somelist if not oughta_pop_it(item)]
or you could use filter or itertools.ifilter to do much the same thing
Michael
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