En Sun, 27 May 2007 10:44:01 -0300, Eric <[EMAIL PROTECTED]> escribió:
> I have some working code, but I realized it is just the way I would > write it in C, which means there is probably a better (more pythonic) > way of doing it. > > Here's the section of code: > > accumulate = firstIsCaps = False > accumStart = i = 0 > while i < len(words): > firstIsCaps = firstIsCapitalized(words[i]) > if firstIsCaps and not accumulate: > accumStart, accumulate = i, True > elif accumulate and not firstIsCaps: > doSomething(words[accumStart : i]) > accumulate = False > i += 1 > > words is a big long array of strings. What I want to do is find > consecutive sequences of words that have the first letter capitalized, > and then call doSomething on them. (And you can ignore the fact that > it won't find a sequence at the very end of words, that is fine for my > purposes). Using groupby: py> from itertools import groupby py> py> words = "Este es un Ejemplo. Los Ejemplos usualmente son tontos. Yo siempre escribo tonterias.".split() py> py> for upper, group in groupby(words, str.istitle): ... if upper: ... print list(group) # doSomething(list(group)) ... ['Este'] ['Ejemplo.', 'Los', 'Ejemplos'] ['Yo'] You could replace your firstIsCapitalized function instead of the string method istitle(), but I think it's the same. See http://docs.python.org/lib/itertools-functions.html -- Gabriel Genellina -- http://mail.python.org/mailman/listinfo/python-list
