Hi James Mathematica says that the determinant of the integer version of this matrix is 2774532096, which is another vote for the answer you have.
Mathematica says that the determinant of the 24-digit real version of your matrix is 2.774532096*10^9, which looks very similar to me. I'd go with Numpy. Regards Mark Westwood PS 13x13 isn't a large matrix ! On Jun 6, 12:10 pm, James Stroud <[EMAIL PROTECTED]> wrote: > Hello All, > > I'm using numpy to calculate determinants of matrices that look like > this (13x13): > > [[ 0. 1. 1. 1. 1. 1. 1. 1. 1. 1. 1. 1. 1. 1.] > [ 1. 0. 1. 4. 1. 9. 4. 4. 1. 1. 4. 9. 4. 9.] > [ 1. 1. 0. 1. 4. 4. 9. 9. 4. 4. 1. 4. 1. 4.] > [ 1. 4. 1. 0. 9. 1. 4. 4. 9. 1. 4. 1. 4. 1.] > [ 1. 1. 4. 9. 0. 4. 4. 4. 1. 4. 1. 9. 4. 9.] > [ 1. 9. 4. 1. 4. 0. 4. 4. 9. 4. 1. 1. 4. 1.] > [ 1. 4. 9. 4. 4. 4. 0. 1. 1. 1. 9. 1. 9. 4.] > [ 1. 4. 9. 4. 4. 4. 1. 0. 4. 1. 9. 4. 4. 1.] > [ 1. 1. 4. 9. 1. 9. 1. 4. 0. 4. 4. 4. 4. 9.] > [ 1. 1. 4. 1. 4. 4. 1. 1. 4. 0. 9. 4. 9. 4.] > [ 1. 4. 1. 4. 1. 1. 9. 9. 4. 9. 0. 4. 1. 4.] > [ 1. 9. 4. 1. 9. 1. 1. 4. 4. 4. 4. 0. 4. 1.] > [ 1. 4. 1. 4. 4. 4. 9. 4. 4. 9. 1. 4. 0. 1.] > [ 1. 9. 4. 1. 9. 1. 4. 1. 9. 4. 4. 1. 1. 0.]] > > For this matrix, I'm getting this with numpy: > > 2774532095.9999971 > > But I have a feeling I'm exceeding the capacity of floats here. Does > anyone have an idea for how to treat this? Is it absurd to think I could > get a determinant of this matrix? Is there a python package that could > help me? > > Many thanks for any answers. > > James -- http://mail.python.org/mailman/listinfo/python-list
