O/S: Windows XP Service Pack 2
Python version: 2.4
Unable to understand how to build a class to handle an exception.
Contents of sample01.py:
import exceptions
class SampleMain:
try:
def __init__(self):
print 'in SampleMain constructor'
def Allowed(self):
print 'in allowed'
def NotYetAllowed(self):
UCError = UnderConstructionError('not yet ready')
raise UCError
except UnderConstructionError, e:
print e.msg
class Error(exceptions.Exception):
def __init__(self):
print 'in base class constructor'
class UnderConstructionError(Error):
def __init__(self, message):
print 'in UnderConstructionError constructor'
self.msg = message
Copy/paste of interactive window:
PythonWin 2.4 (#60, Nov 30 2004, 09:34:21) [MSC v.1310 32 bit (Intel)]
on win32.
Portions Copyright 1994-2004 Mark Hammond ([EMAIL PROTECTED]) -
see 'Help/About PythonWin' for further copyright information.
>>> import sample01
>>> x = sample01.SampleMain()
in SampleMain constructor
>>> x.NotYetAllowed()
in UnderConstructionError constructor
Traceback (most recent call last):
File "<interactive input>", line 1, in ?
File "C:\Python24\sample01.py", line 12, in NotYetAllowed
raise UCError
UnderConstructionError: <unprintable instance object>
>>>
My questions are:
1) What is causing the error described in the Traceback?
2) Given that what I want to happen when the NotYetAllowed() method is
called is:
a) an exception to be raised
b) the exception results in a message getting printed; the message
should come from the place where the exception was raised, and it
should be passed to the exception class as a string object; so in this
case the message that should be printed is 'not yet ready'
c) the exception gets handled with the try/except within the
SampleMain class
My question is: what changes must I make to the code to make that
happen?
Thank you.
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