[EMAIL PROTECTED] wrote:
> def f():
> a = 12
> def g():
> global a
> if a < 14:
> a=13
> g()
> return a
>
> print f()
>
> This function raises an error. Is there any way to access the a in f()
> from inside g().
>
> I could find few past discussions on this subject, I could not find
> the simple answer whether it is possible to do this reference.
>
> -
> Suresh
>
As I'm struggling with this myself at the moment,
this will do the job:
def f():
global a
a = 12
cheers,
Stef Mientki
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