Paul Rubin wrote: > > from itertools import izip > pos = map(dict(izip(l2, count())).__getitem__, l1)
or probably less efficiently ... >>> l1 = [ 'abc', 'ghi', 'mno' ] >>> l2 = [ 'abc', 'def', 'ghi', 'jkl', 'mno', 'pqr'] >>> pos = [ l2.index(i) for i in l1 ] >>> print pos [0, 2, 4] Charles -- http://mail.python.org/mailman/listinfo/python-list
