The use of frozenset can okay when sub-sequences are longer, but for this problem it's slow, and anyway there are situations of repeated data like this that have to be considered:
frozenset( ('a', 'a') )
==>
frozenset(['a'])
For Py2.4 the faster and better solution seems Peter Otten one.
James Stroud solution is O(n^2) and it can become slow for long
lists...
Bear hugs,
Bearophile
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