> One way is to check the length of each dimension. Does any body
> know a simpler way?
No need to check the length of the list:
"""
>>> foo = [0, 1, 2, [3, 4, 5, 6, 7, [8, 9, 10]]]
>>> isInNested(0, foo)
True
>>> isInNested(11, foo)
False
>>> isInNested(3, foo)
True
>>> isInNested(8, foo)
True
"""
def isInNested(k, l):
try:
if k in l:
return True
for i in l:
if isInNested(k, i):
return True
except TypeError:
#l is not iterable
pass
return False
if __name__ == "__main__":
import doctest
doctest.testmod()
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