On 7/23/07, Randy Kreuziger <[EMAIL PROTECTED]> wrote: > I need just the file name from a string containing the path to a file. The > name of the file starts with zeros. This is problematic because the lstrip > function strips them leaving this as the result: > 6128.jpg > > > How do I strip the path without losing the leading zeros in the file name? > > --------------------------------------------- > import sys, os, win32com.client, string > > teststring = 'C:\shoreline\dvd\prep area\800x\\006128.jpg' > print string.lstrip(teststring, 'C:\shoreline\dvd\prep area\800x\\')
lstrip removes *any* of the set of characters in the argument, not the exact string[1]. Use of the string module for lstrip and other functions[2] has been deprecated for using the string methods directly, i.e. teststring.lstrip(...). You should probably be using split (or basename) in the os.path module. Also, use raw strings ( r'\path\to\file' ) to avoid problems with backslashes being interpreted in strings. -Miles [1] http://docs.python.org/lib/string-methods.html [2] http://docs.python.org/lib/node42.html -- http://mail.python.org/mailman/listinfo/python-list
