On Jul 25, 9:04?pm, Steven D'Aprano
<[EMAIL PROTECTED]> wrote:
> On Wed, 25 Jul 2007 18:17:19 -0700, [EMAIL PROTECTED] wrote:
> > On Jul 25, 8:00 pm, Ben Finney <[EMAIL PROTECTED]>
> > wrote:
> >> "[EMAIL PROTECTED]" <[EMAIL PROTECTED]> writes:
> >> > On Jul 24, 6:08 pm, Steven D'Aprano
> >> > <[EMAIL PROTECTED]> wrote:
> >> > > Python already does:
> >> > > "hello-" "world" => "hello-world"
>
> >> > > Propose:
> >> > > 123 456 789 => 123456789
> >> > > 123.456 789 => 123.456789
>
> >> > So, spaces will no longer be delimiters?
>
> >> I don't see how you get that conclusion from Steven's proposal.
>
> > IDLE 1.2c1
> >>>> s = '123 456'
> >>>> s.split()
> > ['123', '456']
>
> > The only way to get '123 456' would be to treat a space as a
> > non-delimiter. But what if those actually WERE two different numbers?
>
> That makes no sense at all. Your example is about splitting a _string_.
Why does it make no sense? Have you never had to
scrape a web page or read a CSV file?
> You can construct and split the string any way you like:
>
> >>> s = '123SURPRISE456'
> >>> s.split('SURPRISE')
>
> ['123', '456']
>
> Notice that the results aren't ints, they are strings.
Duh. I took for granted you knew how to convert
an string to an integer.
>
> To get an int literal, you currently type something like 123456. 123 456
> is currently not valid in Python, it raises an SyntaxError. Try it for
> yourself:
So this proposal would only apply to string literals
at compile time, not running programs?
>
> >>> 123 456
>
> File "<stdin>", line 1
> 123 456
> ^
> SyntaxError: invalid syntax
And I want the same error to occur if my CSV parser
tries to convert '123 456' into a single number.
I don't want it to assume the number is '123456'.
>
> If you want two numbers, you would do exactly the same thing you would now:
>
> >>> x, y = 123, 456
> >>> print "x is %d and y is %d" % (x, y)
>
> x is 123 and y is 456
>
> --
> Steven
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