Dotan Cohen wrote:
> On 10/09/2007, Bryan Olson <[EMAIL PROTECTED]> wrote:
>> Not according to the C standard:
>>
>> When integers are divided, the result of the / operator is
>> the algebraic quotient with any fractional part discarded.(87)
>> If the quotient a/b is representable, the expression
>> (a/b)*b + a%b shall equal a.
>> [...]
>> 87) This is often called ''truncation toward zero''.
>>
>> [International Standard ISO/IEC 9899:1999, Section 6.5.5
>> Multiplicative operators, Paragraph 6 and footnote 87]
>
> This seems most logical to me. Turbo C is against the standard, then.
No, Turbo C is yielding the one-and-only correct result with respect
to the C standard:
(a/b)*b + a%b shall equal a
(-111/10)*10 + -111%10 shall equal -111
(-111/10) evaluates to -11 by the truncate-toward-zero rule
-11*10 + -111%10 shall equal -111
-110 + -111%10 shall equal -111
-111%10 shall equal -1
--
--Bryan
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