On Sun, 16 Sep 2007 00:40:13 +0000, Steven D'Aprano wrote:
> On Sun, 16 Sep 2007 00:05:58 +0000, Marc 'BlackJack' Rintsch wrote:
>
> In *general* the compiler can't tell, but in specific cases it could. A
> (hypothetical) optimizing compiler would tell the difference between:
>
>
> for item in alist[1:5]:
> print item # no possible side-effects
To expand on what Ben said: After conversion to `str` the result is then
given to `sys.stdout.write()` and of course `sys.stdout` could be another
object that changes `alist`.
> for item in alist[1:5]:
> alist.append(item) # side-effects DON'T matter
Side effect do matter here, even in not so pathological cases. There are
cases where you get a different result whether you copy or not even with
plain vanilla `list`\s:
In [153]: alist = [1, 2, 3]
In [154]: for item in alist[1:5]:
.....: alist.append(item)
.....:
In [155]: alist
Out[155]: [1, 2, 3, 2, 3]
In [156]: alist = [1, 2, 3]
In [157]: for item in islice(alist, 1, 5):
.....: alist.append(item)
.....:
In [158]: alist
Out[158]: [1, 2, 3, 2, 3, 2, 3]
Ciao,
Marc 'BlackJack' Rintsch
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