Instead of register_function, use register_instance and provide a _dispatch method in that instance that handles your exception logging.
Pseudo: class MyCalls(object): def _dispatch(self, method, args): try: self.getattr(self, method)(*args) except: handle_logging() server = SimpleXMLRPCServer(("localhost", 8000)) server.register_instance(MyCalls()) server.serve_forever() There might be an easier way... but this works for me. -Jeff On 9/27/07, [EMAIL PROTECTED] <[EMAIL PROTECTED]> wrote: > I have a pretty simple XMLRPCServer, something along the lines of the > example: > > server = SimpleXMLRPCServer(("localhost", 8000)) > server.register_function(pow) > server.register_function(lambda x,y: x+y, 'add') > server.serve_forever() > > Now what I want to do is catch any errors that happen on requests, and > ideally have them emailed to me. I have the email part all taken care > of, I just need to know how to get at the exceptions. > > Thanks in advance for any help, > > Greg > > -- > http://mail.python.org/mailman/listinfo/python-list > -- http://mail.python.org/mailman/listinfo/python-list