On Oct 10, 5:19 am, Shriphani <[EMAIL PROTECTED]> wrote: > Hello all, > > Let us say I have a function like this: > > def efficientFiller(file):
Note that you are shadowing the built-in variable 'file' here. Better use 'filename', or something to that effect. > worthless_list = [] > pot_file = open(file,'r') > pot_file_text = pot_file.readlines() > for line in pot_file_text: > if line.find("msgid") != -1: > message_id = shlex.split(line)[1] > if message_id in dictionary: > number = pot_file_text.index(line) > corresponding_crap = > dictionary.get(message_id) > final_string = 'msgstr' + " " + '"' + > corresponding_crap + '"' + '\n' > pot_file_text[number+1] = final_string > yield pot_file_text > > efficient_filler = efficientFiller("libexo-0.3.pot") > new_list = list(efficient_filler) > print new_list > > I want to plainly get the last value the yield statement generates. > How can I go about doing this please? > > Regards, > Shriphani Palakodety efficient_filler = efficientFiller("libexo-0.3.pot") new_list = list(efficient_filler) last_value = new_list[-1] print last_value # OR efficient_filler = efficientFiller("libexo-0.3.pot") for last_value in efficient_filler: pass print last_value The latter assumes that the last value is the only value you want. -- http://mail.python.org/mailman/listinfo/python-list