Skip Montanaro <[EMAIL PROTECTED]> writes: > Doug> def foogen(arg1): > > Doug> def foogen1(arg2): > Doug> # Some code here > > Doug> # Some code here > Doug> yield_all foogen1(arg3) > Doug> # Some code here > Doug> yield_all foogen1(arg4) > Doug> # Some code here > Doug> yield_all foogen1(arg5) > Doug> # Some code here > Doug> yield_all foogen1(arg6) > > If this idea advances I'd rather see extra syntactic sugar introduced to > complement the current yield statement instead of adding a new keyword.
You can work around the need for something like yield_all, or explicit loops, by defining an "iflatten" generator, which yields every element of its (iterable) argument, unless the element is a generator, in which case we recurse into it: >>> from types import GeneratorType >>> def iflatten(it): ... it = iter(it) ... for val in it: ... if isinstance(val, GeneratorType): ... for v2 in iflatten(val): ... yield v2 ... else: ... yield val To take this one step further, you can define an @iflattened decorator (yes, it needs a better name...) >>> def iflattened(f): ... def wrapper(*args, **kw): ... for val in iflatten(f(*args, **kw)): ... yield val ... return wrapper Now, we can do things like: >>> @iflattened ... def t(): ... def g1(): ... yield 'a' ... yield 'b' ... yield 'c' ... def g2(): ... yield 'd' ... yield 'e' ... yield 'f' ... yield g1() ... yield 1 ... yield g2() ... >>> list(t()) ['a', 'b', 'c', 1, 'd', 'e', 'f'] This can probably be tidied up and improved, but it may be a reasonable workaround for something like the original example. Paul. -- The most effective way to get information from usenet is not to ask a question; it is to post incorrect information. -- Aahz's Law -- http://mail.python.org/mailman/listinfo/python-list
