On Nov 12, 2007 1:41 PM, Donn Ingle <[EMAIL PROTECTED]> wrote: > In an unusual twist of code I have a subclass which overrides a method but > it also needs to call the original method: > > class One: > def add (self, stuff): > self.stuff.append(stuff) > > class Two(One): > def __init__(self, otherstuff): > <MYSTERY>(otherstuff) #otherstuff must go into list within the parent. > #The override - totally different function in this context. > def add (self, data): > self.unrelated.append (data) > > For: > <MYSTERY> > I have tried: > self.One.add( otherstuff ) > No go. > super ( Two, self).add( otherstuff ) > Gives this error:TypeError: super() argument 1 must be type, not classobj > (Which reminds me, how the heck does super work? I always get that error!) >
You need to be a new-style class (that is, you must inherit from object) for super() to work. Other than that, you are using it correctly here. > I could just change the method name to adddata() or something. I could pass > parent references around, but want to avoid that. > > I thought I'd ask about it here. > > \d > > > > -- > http://mail.python.org/mailman/listinfo/python-list > -- http://mail.python.org/mailman/listinfo/python-list