On Dec 6, 7:43 pm, "Gabriel Genellina" <[EMAIL PROTECTED]> wrote: > En Thu, 06 Dec 2007 13:11:09 -0300, Bret <[EMAIL PROTECTED]> escribió: > > > > > For completeness, what I ended up doing is this: > > > server = SimpleXMLRPCServer((host, port)) > > server.socket.settimeout(0.1) > > > ServerWrapper became: > > > def ServerWrapper(): > > while True: > > try: > > server.handle_request() > > if self.done.isSet(): > > break > > except timeout: > > pass > > > And that seems to do the trick! Giving the socket a timeout allows me > > to check the Event more frequently and catch the change within a > > reasonable time. > > Remember that the timeout applies to *all* socket operations; what if the > XML request requires more than 0.1s to read? > If handling large requests is more important than the delay at shutdown > time, consider raising that value. > > -- > Gabriel Genellina
Good point. Thanks! -- http://mail.python.org/mailman/listinfo/python-list
