En Tue, 11 Dec 2007 17:14:14 -0300, Tim Chase <[EMAIL PROTECTED]> escribi�:
> I'm dealing with several large items that have been zipped up to > get quite impressive compression. However, uncompressed, they're > large enough to thrash my memory to swap and in general do bad > performance-related things. I'm trying to figure out how to > produce a file-like iterator out of the contents of such an item. The Time Machine in action again - that's already done, but in SVN. You want the new ZipFile.open(filename) method, which returns a file-like object. Either wait until the 2.6 release, or get the zipfile.py source from http://svn.python.org/view/python/trunk/Lib/zipfile.py and see if it works with the current 2.5 release. (I think it should work OK) -- Gabriel Genellina -- http://mail.python.org/mailman/listinfo/python-list
