I have
listA=[1,2,3,4,5,4,3,4,3,2,1]
and I want a list of only the unique members.
This seems inefficient, but works fine over my small sample lists:
listA=[a for a in set(listA)]
Is there a more efficient approach for cases where listA is large?
no. Even though the code can be a little simpler:
listA = list(Set(listA))
You don't even need to convert it to a list. You can just iterate over the set.
>>> la = [1,2,3,4,3,2,3,4,5] >>> from sets import Set >>> sa = Set(la) >>> for itm in sa: ... print itm 1 2 3 4 5
--
hilsen/regards Max M, Denmark
http://www.mxm.dk/ IT's Mad Science -- http://mail.python.org/mailman/listinfo/python-list
