Dear list,
If you ask: why do you choose these names? The answer is: they need to be conformable with other functions, parameter names.
I have a function that pretty much like:
def output(output=''): print output
and now in another function, I need to call output function, with again keyword parameter output
def func(output=''): output(output=output)
Naturally, I get 'str' object is not callable. Is there a way to tell func that the first output is actually a function? (like in C++, ::output(output) )
Thanks. Bo
What I'd suggest is :
def func(output=''): gobals()["output"](output=output)
that way, the function resolution is still dynamic, but you explicitly ask for a name global and not local ...
Pierre -- http://mail.python.org/mailman/listinfo/python-list
