[EMAIL PROTECTED] wrote: > Given a bunch of arrays, if I want to create tuples, there is > zip(arrays). What if I want to do the opposite: break a tuple up and > append the values to given arrays: > map(append, arrays, tupl) > except there is no unbound append() (List.append() does not exist, > right?). > > Without append(), I am forced to write a (slow) explicit loop: > for (a, v) in zip(arrays, tupl): > a.append(v) > > I assume using an index variable instead wouldn't be much faster. > > Is there a better solution? > > Thanks, > igor >
But it *does* exist, and its named list.append, and it works as you wanted. >>> list.append <method 'append' of 'list' objects> >>> a = [[],[]] >>> map(list.append, a, (1,2)) [None, None] >>> a [[1], [2]] >>> map(list.append, a, (3,4)) [None, None] >>> a [[1, 3], [2, 4]] >>> map(list.append, a, (30,40)) [None, None] >>> a [[1, 3, 30], [2, 4, 40]] Gary Herron -- http://mail.python.org/mailman/listinfo/python-list
