I've figured it out, it is default argument. print y() gives 13 as result.
It's a bit evil though. I hope this post will be useful some newbie like i'm now someday :) On Jan 10, 7:25 pm, "[EMAIL PROTECTED]" <[EMAIL PROTECTED]> wrote: > I'm reading this > page:http://www.ps.uni-sb.de/~duchier/python/continuations.html > and I've found a strange usage of lambda: > > #################### > Now, CPS would transform the baz function above into: > > def baz(x,y,c): > mul(2,x,lambda v,y=y,c=c: add(v,y,c)) > > ################### > > What does "y=y" and "c=c" mean in the lambda function? > I thought it bounds the outer variables, so I experimented a little > bit: > > ################# > x = 3 > y = lambda x=x : x+10 > > print y(2) > ################## > > It prints 12, so it doesn't bind the variable in the outer scope. -- http://mail.python.org/mailman/listinfo/python-list
