On Jan 22, 3:20 am, Alan Isaac <[EMAIL PROTECTED]> wrote:
> I want to generate sequential pairs from a list.
> Here is a way::
>
> from itertools import izip, islice
> for x12 in izip(islice(x,0,None,2),islice(x,1,None,2)):
> print x12
>
> (Of course the print statement is just illustrative.)
> What is the fastest way? (Ignore the import time.)
>
> Thanks,
> Alan Isaac
Don't know the fastest, but here's a very concise way:
from itertools import izip
def ipairs(seq):
it = iter(seq)
return izip(it, it)
>>> list(pairs(xrange(10)))
[(0, 1), (2, 3), (4, 5), (6, 7), (8, 9)]
>>> list(pairs('hello'))
[('h', 'e'), ('l', 'l')]
--
Arnaud
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