On Jan 30, 9:50 am, Santiago Romero <[EMAIL PROTECTED]> wrote: > On 30 ene, 08:09, Paul Rubin <http://[EMAIL PROTECTED]> wrote: > > > Santiago Romero <[EMAIL PROTECTED]> writes: > > > > > >>> li = [1,2,3,4,5] > > > > >>> filter(lambda x: x != 3, li) > > > > [1, 2, 4, 5] > > > > I haven't measured it, but this should be the fast solution in all > > > the thread ... > > > li.remove(3) is probably faster. > > But that only removes the first ocurrence of item==3. > > In a = [1, 2, 3, 3, 3, 4, 3, 3, 2, 3], the filter solution will > efectively remove all items with value == 3 while li.remove(3) will > only remove the first ocurrence. > > Bye!
from itertools import ifilter print [x for x in ifilter(lambda x: x != 99, li)] Will this one be faster or slower than filter? -- http://mail.python.org/mailman/listinfo/python-list