'in' has a lower operator precedence than '=='
('t' in sample) == True
would fix the operator precedence.
On Feb 8, 2008 11:09 AM, c james <[EMAIL PROTECTED]> wrote:
> Try this
>
> >>> sample = {'t':True, 'f':False}
> >>> 't' in sample
> True
> >>> type('t' in sample)
> <type 'bool'>
> >>> 't' in sample == True
> False
>
> Why is this? Now try
> >>> bool('t' in sample) == True
> True
>
> Can someone explain what is going on?
>
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