Arnaud Delobelle wrote: (...) > > from itertools import chain > > def overlaps(lst): > bounds = chain(*(((x[1],i), (x[2], i)) for i,x in enumerate(lst)))
imho, this is a uselessly painful equivalent of
bounds = ((x[k],i) for i,x in enumerate(lst) for k in (1,2))
Cheers, BB
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