"Adam W." <[EMAIL PROTECTED]> writes: > I am using the xml.sax package, and I'm running into a little > problem. When I use the parse(url, ContentHandler()) method, I don't > know what parse() is naming the instance of ContentHandler.
I'm not sure what you're asking. Why do you need to know the internal name for that parameter? > I have a sub-class of ContentHandler make a dictionary of what it > parses, but the problem is I don't know the name of instance for me > to get at it. The only way I have gotten at my dict is to declare it > a global value, and I know that is not the right way to do it. Perhaps this:: handler = ContentHandler() result = parse(url, handler) -- \ "All my life I've had one dream: to achieve my many goals." -- | `\ Homer, _The Simpsons_ | _o__) | Ben Finney -- http://mail.python.org/mailman/listinfo/python-list