On Feb 22, 11:20 am, rh0dium <[EMAIL PROTECTED]> wrote:
>
> found = False
> for item in a:
> if item[0] == element[0]
> found = True
> break
> if not found:
> a.append(element)
>
> But this is just ugly - Is there a simpler way to interate over all
> items in a without using a found flag?
>
> Thanks
for item in a:
if item[0] == element[0]
break
else: # only called if we never 'break' out of the for loop
a.append(element)
But what about a dict?
adict = dict((elem[0],elem) for elem in a)
if item[0] not in adict:
adict[item[0]] = item
# need the final list?
a = adict.values()
No list searching, and will scale well if a gets real long.
-- Paul
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