Farsheed Ashouri , > Here is my script > #********************************************************************** > #********************************************************************** > import threading > import socket > def openSocket(portNum): > mySocket = socket.socket ( socket.AF_INET, socket.SOCK_STREAM ) > mySocket.bind ( ( '', portNum ) ) > mySocket.listen ( 1 ) > channel, details = mySocket.accept() > msg = channel.recv(4096) > > class CmdPortThread( threading.Thread ): > def run( self ): > openSocket(6000) > > def fakeCommandPort(): > CmdPortThread().start() > fakeCommandPort()
> If works perfect with python 2.5.2. Now I want to convert it to > standalone program. > but the .exe file fails to run without any error. are you sure that it fails to run? I expect it to run, and exit immediately after fakeCommandPort(). That is: there is nothing more to do in the main thread, so the application exits. To learn more, add prints and use the usual if __name__=='__main__' class CmdPortThread( threading.Thread ): def run( self ): print "Thread CmdPortThread running" openSocket(6000) if __name__=='__main__': print "Mese running" fakeCommandPort() print "Mese done starting Thread" Harald -- http://mail.python.org/mailman/listinfo/python-list