> (defun addn (n) > (lambda (x) > (+ x n))) > > And Lisp's "macro language" isn't involved at all here.
(macroexpand-1 '(lambda (x) (+ x n))) => #'(LAMBDA (X) (+ X N)) Also, #' is a read-macro. Fully expanded the #'(lambda expression would be (function (lambda (x) (+ x n))) Then there's the "defun" macro . . . . :-) -- Fred Gilham [EMAIL PROTECTED] A common sense interpretation of the facts suggests that a superintellect has monkeyed with physics, as well as with chemistry and biology, and that there are no blind forces worth speaking about in nature. --- Fred Hoyle -- http://mail.python.org/mailman/listinfo/python-list
