On Thu, 20 Mar 2008 03:24:49 -0700, Dravidan wrote:
> I am trying to read some byte data as a string then using a library to
> convert them a code:
>
>>>>reader = csv.DictReader(open('table.txt'))
>>>>def eleFind(value):
>>>> for row in reader:
>>>> if row['byteCode'] == value:
>>>> print row['Element']
>>>> return
>>>> else:
>>>> print "No Match Found:"
>>>>eleFind('\x00\x00')
>
> My table contains:
>
> \x00\x00,0000
> \x01\x00,0000
> ......
>
> The program errors out. How can I fix/overide this backslash issue.
What does `errors out` mean?
It won't find two zero bytes. What you give at the `eleFind()` call are
just *two* characters with a byte value of zero:
In [116]: len('\x00\x00')
Out[116]: 2
In [117]: print '\x00\x00'
In [118]: len('\\x00\\x00')
Out[118]: 8
In [119]: print '\\x00\\x00'
\x00\x00
The backslash has a special meaning in string literals. If you don't want
this meaning, you have to escape it with another backslash.
Ciao,
Marc 'BlackJack' Rintsch
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