On Mar 26, 5:45 am, hellt <[EMAIL PROTECTED]> wrote: > On 26 ÍÁÒ, 02:30,kellygreer1<[EMAIL PROTECTED]> wrote: > > > What is the best way to filter a Python list to its unique members? > > I tried some method using Set but got some "unhashable" error. > > > lstone = [ 1, 2, 3, 3, 4, 5, 5, 6 ] > > # how do i reduce this to > > lsttwo = [ 1, 2, 3, 4, 5, 6 ] > > > Is there a page on this in the Python in a Nutshell or the Python > > Cookbook? > > Did I miss something? > > > Kelly Greer > > [EMAIL PROTECTED] > > change nospam to yahoo > > or just look this thread for a fastest > solutionhttp://groups.google.com/group/comp.lang.python/browse_frm/thread/709...
How come the Set() thing seems to work for some people and I get the 'unhashable' error? How do you test for 'membership' on a dictionary? # where tmp is the non-unique list # dct is a dictionary where each unique key will be tied to a count (the value) # for testing I was setting the count to 0 for v in tmp: if not v in dct: dct[v] = 0 # I get unhashable error here. # Even if I write it. for v in tmp: if not v in dct.keys(): dct[v] = 0 What am I missing? Thanks, Kelly -- http://mail.python.org/mailman/listinfo/python-list