On Apr 11, 6:06 am, casevh <[EMAIL PROTECTED]> wrote: > On Apr 10, 9:28 pm, bdsatish <[EMAIL PROTECTED]> wrote: > > > How does (a/b) work when both 'a' and 'b' are pure integers ? > > Python defines the quotient and remainder from integer division so > that a = qb + r and 0<=r < abs(b). C/C++ lets the remainder be > negative.
On Apr 11, 6:06 am, casevh <[EMAIL PROTECTED]> wrote: > On Apr 10, 9:28 pm, bdsatish <[EMAIL PROTECTED]> wrote: > > > How does (a/b) work when both 'a' and 'b' are pure integers ? > > Python defines the quotient and remainder from integer division so > that a = qb + r and 0<=r < abs(b). C/C++ lets the remainder be > negative. On Apr 11, 6:06 am, casevh <[EMAIL PROTECTED]> wrote: > On Apr 10, 9:28 pm, bdsatish <[EMAIL PROTECTED]> wrote: > > > How does (a/b) work when both 'a' and 'b' are pure integers ? > > Python defines the quotient and remainder from integer division so > that a = qb + r and 0<=r < abs(b). C/C++ lets the remainder be > negative. (Puts language lawyer hat on) That's not accurate: r can be negative. To quote the reference manual: 'The modulo operator always yields a result with the same sign as its second operand (or zero); the absolute value of the result is strictly smaller than the absolute value of the second operand.' divmod(9, -2) # (-5, -1) Both C and Python define q = a / b and r = a % b to satisfy a = q * b + r, where -abs(b) < r < abs(b). Where they differ: Python: r has the same sign of b (or 0). C99: r has the same sign as a (or 0). C89 (Standard C): It's implementation defined what sign r has if either a or b is negative. This means python already has C-like behaviour... it's compatible with standard C, although not with C99. -- Paul Hankin -- http://mail.python.org/mailman/listinfo/python-list
