Below is a (flawed) one line RegEx that checks curly brackets (from awk/c/python input) are being matched. Is there a one liner for doing this in python?
ThanX N re_open_close="(((\{))[^{}]*((?(0)\})))+" re_open_close=re.compile(re_open_close) tests=""" { this is a test BAD { this is a test } OK { this is a test } { this is a test } OK { this is a test } { this { this is a test } is a test } OK { this is a test { this { this is a test } is a test } missing close BAD """.splitlines()[1:] for test in tests: if bool(re_open_close.search(test)) == bool(re.search("OK",test)): print "DETECTED:",test else: print "MISSED:",test [linux]$ python ./re_matching.py DETECTED: { this is a test BAD DETECTED: { this is a test } OK DETECTED: { this is a test } { this is a test } OK DETECTED: { this is a test } { this { this is a test } is a test } OK MISSED: { this is a test { this { this is a test } is a test } missing close BAD -- http://mail.python.org/mailman/listinfo/python-list