On May 9, 6:25 am, dmitrey <[EMAIL PROTECTED]> wrote: > Ok, I use Python 2.5 but I try my code to remain Python 2.4 and > (preferable) 2.3 compatible. > Are there other solutions? > D. > > On 9 ôÒÁ, 13:17, Paul Hankin <[EMAIL PROTECTED]> wrote: > > > On May 9, 11:04šam, dmitrey <[EMAIL PROTECTED]> wrote: > > > > list1 = ['elem0', 'elem1', 'elem2', 'elem3', 'elem4', 'elem5'] > > > and > > > list2 = [0, 2, 4] # integer elements > > > > howto (I mean most simple recipe, of course) form list3 that contains > > > elements from list1 with indexes from list2, i.e. > > > list3 = [list1[i] for i in list2] > > > -- > > Paul Hankin
Why don't you try Paul's suggestion under Python 2.3 and see what happens? -- http://mail.python.org/mailman/listinfo/python-list
