Guillermo wrote:
This must be very basic, but how'd you pass the same *args several
levels deep?
def func2(*args)
print args # ((1, 2, 3),)
# i want this to output (1, 2, 3) as func1!
# there must be some better way than args[0]?
def func1(*args):
print args # (1, 2, 3)
func2(args)
func1(1,2,3)
Me, myself and I wrote:
func2(*args)
Thats all. See
http://docs.python.org/tut/node6.html#SECTION006740000000000000000
That was a bit unclear. You should use func2(*args) when you call the
function.
/MiO
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