Cameron wrote:
On May 30, 1:04 pm, "Diez B. Roggisch" <[EMAIL PROTECTED]> wrote:
Cameron schrieb:
I was reading this <a href="thishttp://www.paulgraham.com/icad.html";>Paul
Graham article</a> and he builds an accumuator generator function in
the appendix. His looks like this:
<pre>
def foo(n):
s = [n]
def bar(i):
s[0] += i
return s[0]
return bar
</pre>
Why does that work, but not this:
<pre>
def foo(n):
s = n
def bar(i):
s += i
return s
return bar
</pre>
Because python's static analysis infers s as being a variable local to
bar in the second case - so you can't modify it in the outer scope.
In the future, you may declare
def bar(i):
nonlocal s
...
Diez
thanks for the response. Just to make sure I understand- Is the reason
it works in the first case because s[0] is undefined at that point (in
bar), and so python looks in the outer scope and finds it there?
You can refer to variables in enclosing scopes, just not redefine them in that
same scope. That's why in the first example, bar can refer to to s (defined in
foo). By assigning to s[0], it modifies the list, which is OK; trying to
redefine the name 's' (like the second example tries to do) would not be OK.
Also see: http://zephyrfalcon.org/labs/python_pitfalls.html (pitfall #6).
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http://4.flowsnake.org/
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