En Mon, 02 Jun 2008 18:56:08 -0300, jay graves <[EMAIL PROTECTED]>
escribió:
On Jun 2, 4:02 pm, Larry Bates <[EMAIL PROTECTED]> wrote:
I think what you want is:
def write_err(*args):
from sys import stderr
stderr.write("\n".join([str(o) for o in args]))
Slight nitpick. If you are using version >= 2.4 you could use a
generator expression instead of a list comprehension to avoid building
and throwing away a list.
"\n".join(str(o) for o in args)
http://www.python.org/dev/peps/pep-0289/
Very unlikely to yield a material time difference in this case but
cleaner IMO.
Still nitpicking: using a generator expression in this case has no
advantage. The first thing that str.join does is to create a list out of
its argument (unless it is already a list or a tuple). In fact, a list
comprehension is faster here.
--
Gabriel Genellina
--
http://mail.python.org/mailman/listinfo/python-list
