"Mensanator" <[EMAIL PROTECTED]> wrote in message news:[EMAIL PROTECTED] | On Jun 5, 10:42?pm, John Salerno <[EMAIL PROTECTED]> wrote: | > Is it possible to write a list comprehension for this so as to produce a | > list of two-item tuples? | > | > base_scores = range(8, 19) | > score_costs = [0, 1, 1, 1, 1, 1, 1, 2, 2, 3, 3] | > print zip(base_scores, score_costs) | > | > I can't think of how the structure of the list comprehension would work | > in this case, because it seems to require iteration over two separate | > sequences to produce each item in the tuple.
Which is exactly the purpose of zip, or its specialization enumerate! | > zip seems to work fine anyway, but my immediate instinct was to try a | > list comprehension (until I couldn't figure out how!). And I wasn't sure | > if list comps were capable of doing everything a zip could do. | | base_scores = range(8, 19) | score_costs = [0, 1, 1, 1, 1, 1, 1, 2, 2, 3, 3] | print zip(base_scores, score_costs) | | s = [(i+8,j) for i,j in enumerate( [0, 1, 1, 1, 1, 1, 1, 2, 2, 3, 3])] | print s | | ##>>> | ##[(8, 0), (9, 1), (10, 1), (11, 1), (12, 1), (13, 1), (14, 1), (15, | 2), (16, 2), (17, 3), (18, 3)] | ##[(8, 0), (9, 1), (10, 1), (11, 1), (12, 1), (13, 1), (14, 1), (15, | 2), (16, 2), (17, 3), (18, 3)] | ##>>> Of course, enumerate(iterable) is just a facade over zip(itertools.count(), iterable) -- http://mail.python.org/mailman/listinfo/python-list
