takayuki wrote:
for letter in avoid:
if letter in word:
break
else:
print word
Take the word 'dog', for example. What the above loop is doing is
basically this:
1. for letter in avoid uses 'a' first
2. is 'a' in 'dog'?
3. no, so it prints 'dog'
4. go back to for loop, use 'b'
5. is 'b' in 'dog'?
6. no, so it prints 'dog' again
7. go back to for loop.....
Since it goes sequentially through 'abcd', it will say that the first
three letters are not in 'dog', and therefore print it three times. Then
it finally sees that 'd' *is* in dog, so it skips it the fourth time
through the loop.
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