En Tue, 17 Jun 2008 23:04:16 -0300, Asun Friere <[EMAIL PROTECTED]> escribió:
> On Jun 17, 5:33 pm, "Gabriel Genellina" <[EMAIL PROTECTED]> > wrote: >> En Tue, 17 Jun 2008 02:25:42 -0300, Lie <[EMAIL PROTECTED]> escribió: > >> >> > Basically 'a is b' and 'not(a is b)' is similar to 'id(a) == id(b)' >> > and 'not(id(a) == id(b))' >> >> No. > ... >> ... The above statement is not. A counterexample: >> >> py> [] is [] >> False >> py> id([])==id([]) >> True >> > But that's not what he said, he used 'a' and 'b' which are names, not > anonymous objects. > Fairer would be, > a = [];b = [] > id(a) == id(b) If you limit yourself to interpret 'a' and 'b' as actual names, yes, the statement is true. But I thought of them as placeholders or metasyntactic names - like in "abs(x) returns the absolute value of x", where x may represent *any* expression, not just a single name. Under this general interpretation the statement is not true anymore. (This thread is getting way above 10000cp...) -- Gabriel Genellina -- http://mail.python.org/mailman/listinfo/python-list
