In article <[EMAIL PROTECTED]>,
James Stroud <[EMAIL PROTECTED]> wrote:
> Hello,
>
> I have strings represented as a combination of an alphabet (AGCT) and a an
> operator "/", that signifies degeneracy. I want to split these strings into
> lists of lists, where the degeneracies are members of the same list and
> non-degenerates are members of single item lists. An example will clarify
> this:
>
> "ATT/GATA/G"
>
> gets split to
>
> [['A'], ['T'], ['T', 'G'], ['A'], ['T'], ['A', 'G']]
How about this?
import re
s = "ATT/GATA/G"
result1 = re.findall(r"./.|.", s)
consensus = [c.split("/") for c in result1]
--
Doug Schwarz
dmschwarz&urgrad,rochester,edu
Make obvious changes to get real email address.
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