Dave wrote:
arrrggg, now I feel really dumb..
hitNum = 0
stopCnt = 6 + hitNum
offSet = 5
for i in range(0,10,1):
for x in range(hitNum,len(inLst), 1):
print hitNum, stopCnt
if x == stopCnt: break
hitLst.append(inLst[x])
hitNum +=offSet
stopCnt+=offSet
print hitLst
Beers, Dave
On Aug 13, 12:58 am, Dave <[EMAIL PROTECTED]> wrote:
On Aug 13, 12:35 am, Larry Bates <[EMAIL PROTECTED]> wrote:
Dave wrote:
Hey there, having a bit of problem iterating through lists before i go
on any further, here is
a snip of the script.
--
d = "a1 b1 c1 d1 e1 a2 b2 c2 d2 e2 a3 b3 c3 d3 e3 a4 b4 c4 d4 e4 a5 b5
c5 d5 e5"
inLst = d.split()
hitLst = []
hitNum = 0
stopCnt = 6 + hitNum
for i in range(hitNum,len(inLst), 1):
if i == stopCnt: break
hitLst.append(inLst[i])
print hitLst
--
$ python helper.py
['a1', 'b1', 'c1', 'd1', 'e1', 'a2']
This works fine for my purposes, what I need is an outer loop that
goes through the original list again and appends my next request.
ie.
hitNum = 5
which will return:
['a2', 'b2', 'c2', 'd2', 'e2', 'a3']
and append it to the previous one.
ie:
['a1', 'b1', 'c1', 'd1', 'e1', 'a2']
['a2', 'b2', 'c2', 'd2', 'e2', 'a3']
not really sure how to do this right now though, been trying several
methods with no good results.
btw, just creating lagged values (sort of shift registers) on the
incoming signal
Many thanks,
Dave
Dave,
You are going to need to supply us with more info to help.
1) Are you always going to want to get 6 elements from the list
2) Are you always going to want to step by 5 elements as your offset each time
through the outer loop?
3) Is your requirement just to split inLst into equal length lists and append
them together into a list?
Depending on your answers this might be quite easy.
-Larry
Hi Larry, well to answer your questions.
1) Are you always going to want to get 6 elements from the list
yes for this example, but this will change depending on the length of
the sig.
hitNum will be changing depending on what element I need to lag ie:
if hitNum = 1
['b1', 'c1', 'd1', 'e1', 'a2', 'b2']
so I will be lagging the b elements.
2) Are you always going to want to step by 5 elements as your offset
each time
through the outer loop?
I think I just answered this
3) Is your requirement just to split inLst into equal length lists and
append
them together into a list?
yes
Thanks for all your help,
Dave
This can also be written as:
d = "a1 b1 c1 d1 e1 a2 b2 c2 d2 e2 a3 b3 c3 d3 e3 " \
"a4 b4 c4 d4 e4 a5 b5 c5 d5 e5"
inLst = d.split()
sliceLen = 6
step = 5
offset = 1
hitLst = list()
for n in xrange(len(inLst)/step):
start = offset + n * step
hitLst.append(inLst[offset:offset + sliceLen])
print hitLst
-Larry
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