afraid not.. simple to create your own, NOTE that key words can be supplied
more than once. Hence...
============================================
import urllib
def urldecode(query):
d = {}
a = query.split('&')
for s in a:
if s.find('='):
k,v = map(urllib.unquote, s.split('='))
try:
d[k].append(v)
except KeyError:
d[k] = [v]
return d
s = 'Cat=1&by=down&start=1827&start=1234&anotherCat=me%3Dow%7e'
print urldecode(s)
====================================================
prints out following and preserves the order of inputs for those keys given
more than once as with 'start' key
{'start': ['1827', '1234'], 'anotherCat': ['me=ow~'], 'by': ['down'], 'Cat':
['1']}
hope that helps..
Edwin
-----Original Message-----
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] Behalf Of [EMAIL PROTECTED]
Sent: Thursday, August 14, 2008 12:32 PM
To: python-list@python.org
Subject: urldecode function?
hi
is there a function that does the opposite of urllib.urlencode?
for example
urldecode('Cat=1&by=down&start=1827')
returns a dictionary with {'Cat':1, 'by':'down','start':1827)
thanks
The information contained in this message and any attachment may be
proprietary, confidential, and privileged or subject to the work
product doctrine and thus protected from disclosure. If the reader
of this message is not the intended recipient, or an employee or
agent responsible for delivering this message to the intended
recipient, you are hereby notified that any dissemination,
distribution or copying of this communication is strictly prohibited.
If you have received this communication in error, please notify me
immediately by replying to this message and deleting it and all
copies and backups thereof. Thank you.
--
http://mail.python.org/mailman/listinfo/python-list
