On Thu, 14 Aug 2008 18:23:21 -0300, ariel ledesma wrote: > i see now, so i guess that's also why id() returns the same address for > them as well...
It just have to work like this. a is b is actually equal to: id(a) == id(b) so there is no other way for id() in such case. Hope this helps. -- Regards, Wojtek Walczak, http://www.stud.umk.pl/~wojtekwa/ -- http://mail.python.org/mailman/listinfo/python-list
