lee a écrit :
hi,
i have a dictionary as follows :
kev : {'phno': ['dgsd', 'gsdg', 'dfsdf', 'g'], 'email': ['dg',
'sgsd', 'sdfsdf', 'gdf'], 'name': ['ds', 'dsg', 'dsfds', 'fgdf'],
'address': ['sdg', 'dsgsdg', 'sdf', 'dfg']}
if user is enters the 3rd item of key phno,
ie "dfsdf" in my dict,
how can i find it is the third item in the internal list of phno of
that dictionary?
It's quite simple (hint : read the FineManual(tm) for dict.items() and
list.index()), but 1/totally inefficient and 2/not garanteed to yield a
single value (what if 'dfsdf' happens to be also the 4th item of the
list bound to key 'address' ?).
May I suggest you rethink your data structure instead ? What you have
here is obviously a collection of 'phno/email/name/address'records.
These records shouldn't be split across different objects. Assuming
'phno' is a unique identifier for each record, a better data structure
would be:
records = {
'dgsd' : {'email': 'dg', 'name' : 'ds', 'address' : 'sdg'},
'gsdg' : {'email': 'sgsd', 'name':'ds', 'address' : 'dsgsdg'},
# etc
}
This way, the lookup is as simple and efficient as possible.
My 2 cents....
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